Problem:

The partial molar volumes of acetone and chloroform in a mixture in which the mole fraction of chloroform is 0.47 are 74.1 ml/mol and 80.2 ml/mol, respectively. What is the volume of a solution of mass 100 g?

Solution:

The total volume of a mixture is :

V= nAVA + nBVB .

We need to find nA and nB. From the definition of molar fractions (chapter 1.2(d)), one can easily show that

xAnB = xBnA.

Then, using the equation for the total mass of the solution:

m= nAMA + nBMB,

we can easily solve for nA and nB. Substituting nA and nB to the final equation, we get:

V= m(xAVA + xBVB)/(xAMA + xBMB).

If we choose that A is acetone and B is chloroform, the volume of the mixture is

V= 88.8 ml.