Table for CAN(5,k,23) for k up to 10000

Locate the k in the first column that is at least as large as the number of factors in which you are interested. Then let N be the number of rows (tests) given in the second column. A CA(N;5,k,23) exists according to a construction in the reference (cryptically) given in the third column. The accompanying graph plots N vertically against log k (base 10).

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246436343orthogonal array
269765623fuse symbols
2814348903fuse symbols
4814758571Martirosyan-Tran van Trung
5220897609Martirosyan-Tran van Trung
5428586985Martirosyan-Tran van Trung
5628591079Martirosyan-Tran van Trung
6033278583Martirosyan-Tran van Trung
6235656301Martirosyan-Tran van Trung
6435660395Martirosyan-Tran van Trung
6836102547Martirosyan-Tran van Trung
7036106641Martirosyan-Tran van Trung
7236110735Martirosyan-Tran van Trung
7636585639Martirosyan-Tran van Trung
7836589733Martirosyan-Tran van Trung
8036593827Martirosyan-Tran van Trung
8236843561Martirosyan-Tran van Trung
8436847655Martirosyan-Tran van Trung
9236929535Martirosyan-Tran van Trung
9637185571Martirosyan-Tran van Trung
10447445671Martirosyan-Tran van Trung
10860195091Martirosyan-Tran van Trung
11260199185Martirosyan-Tran van Trung
53064363421linear hash family
53182297579extend by one factor
53297656221linear hash family
105898580177Martirosyan-Tran van Trung
106099092249Martirosyan-Tran van Trung
1062117026407Martirosyan-Tran van Trung
1064132385049Martirosyan-Tran van Trung
2210132827131linear hash family
10000135163183Power 23^3