Chapter 28 50. (a) by integration, U_C = (1/2)C(EMF)² and energy out from battery = C(EMF)² (b) by integration, heat from resistor = (1/2)C(EMF)² 52. 2.35 MOhms Fishbane Problems - Chapter 28 57. proof Chapter 31 8. 0.452 V 12. (a) t=0, B=126 microT; t=0.5s, B=0; t=1s, B=-126 microT (b) 50.3 nV 14. 15.5 microC 18. (a) f (b) pi²a²Bf 22. (a) 598 nV (b) CCW 28. v=mgR/B²L² 30. (a) 85.2 Wb (b) 56.8 V (c) n=1 32. path 1, -1.07 mV; path 2, -2.40 mV; path 3, 1.34 mV 34. 0.151 N/C 38. (a) (mu0)i/W (b) (mu0)(pi)R²/W 54. just closed (a) 2 A (b) 0 (c) 2 A (d) 0 (e) 10 V (f) 2 A/s t=infinity (a) 2 A (b) 1 A (c) 3 A (d) 10 V (e) 0 (f) 0 58. (a) 238.7 W (b) 154.8 W (c) 393.5 W 60. (a) 18.7 J (b) 5.10 J (c) 13.6 J 62. 5.58 A 66. (a) 1.26 mT (b) 0.628 J/m³ 72. (mu0)Nn(pi)R² plus explanation 74. ((mu0)(N1)(N2)h/2(pi))ln(b/a) P90. (a) 43.9 Mm/s² to the right (b) zero (c) 43.9 Mm/s² to the left Fishbane Problems - Chapter 33 46. DiffEq is -I(t)R - L(dI/dt) = 0 Chapter 32 28. (a) 1.89 pT (b) graph; at 10 cm, B = 0.565 pT 30. 750 kV/s 32. 7193 GV/(ms) 34. (a) 21.2 nA down (b) CW from above 38. (a) (4/3) A (b) at R/4 and at 4R Chapter 33 12. (a) 3.6 mH (b) 1326 Hz (c) 189 microseconds 32. 0.6 A for all frequencies 34. (a) 5.22 mA (b) zero (c) 4.52 mA 36. (a) 39.1 mA (b) zero (c) -33.9 mA 44. (a) 16.6 Ohms (b) 422 Ohms (c) 521 mA (d) 33.2 Ohms (e) 408 Ohms (f) 539 mA 50. 100 V (you must carefully explain why) 52. (a) taking energy (b) supplying energy 60. (a) 76.4 mH (b) yes; 17.8 Ohms; resistor would consume energy, not store it G1. proof G2. proof G3. proof G4. proof Chapter 34 2. (a) 4.71 mHZ (b) 212 s 6. 4.74 m 14. 1.19 MW/m² 16. Bmax = 3.42 microT; Emax = 1.03 kV/m 34. 4.55 x 10^-4 38. 19.0 W/m² 40. (a) 15.9% (b) 84.1%