```Chapter 24
32. 563 nJ/m³
Chapter 26
12. 25 Ohm - 7.00 A; 20 Ohm - 9.95 A
58. 8.60 V
84. (a) 7.10 J
(b) 3.62 kW
(c) 1.81 kW
Fishbane Problems - Chapter 28
57. proof
Halliday 2nd Ed Problems - Chapter 29
22. (a) by integration, U_C = (1/2)C(EMF)² and
energy out from battery = C(EMF)²
(b) by integration, heat from resistor = (1/2)C(EMF)²
Chapter 29
2. (a) before - 14.4 micro Wb; after - zero
(b) 0.360 mV
6. (a) 0.0302 V + (0.302 mV/s³)t³
(b) 0.113 mA
24. (a) 3.00 V
(b) towards top of page
(c) 0.800 N to the right
(d) 6.00 W for each
27. (c) 530 microN/C
(d) counterclockwise
32. (a) 950 microV
(b) 109 microH
54. (a) (mu_0)i/(2pir) into page
(b) L(mu_0)i(dr)/(2pir)
(c) ln(b/a)L(mu_0)i/(2pi)
(d) ln(b/a)L(mu_0)(di/di)/(2pi)  CCW
(e) 0.506 microV
76. (a) from a to b
(b) (Rmg)tan(phi)/(L²B²cos(phi))
(c) (mg)tan(phi)/(LB)
(d) Rm²g²tan²(phi)/(L²B²)
(e) same answer as in (d) by a different method
Wolfson - Chapter 30
42. (a) (mu0)J(|z|)           (b) (mu0/2)Jh
48. (a) (mu0)I(sqrt(n²+(1/2piR)²))
(b) INVtan(1/2(pi)nR)
57. proof; out of the page
58. proof; out of the page
68. (a) (pi/3)R²J_0
(b) (mu0/6r)R²J_0
(c) (mu0/2)rJ_0(1-(2r/3R))
HRW PROBLEM SUPPLEMENT #1 - CHAPTER 30
73. (a) 4.8 mT
(b) 0.933 mT
(c) zero
Fishbane Problems - Chapter 30
32. (a) Bmax = 174 microT; Bmin = 139 microT    <== these answers use
(b) 0.140 microWb  (1 Wb = 1 T⋅m²)              HRW's value of rho_CU
(c) heating rate is 1.57 W; doesn't get very hot   (16.9 nOhms⋅m)
(a) Bmax = 175 microT; Bmin = 140 microT    <== these answers use
(b) 0.141 microWb  (1 Wb = 1 T⋅m²)              Wolfson's value
(c) heating rate is 1.58 W; doesn't get very hot  (16.8 nOhms⋅m)
(a) Bmax = 171 microT; Bmin = 137 microT    <== these answers use
(b) 0.138 microWb  (1 Wb = 1 T⋅m²)              Y&F's value
(c) heating rate is 1.54 W; doesn't get very hot  (17.2 nOhms⋅m)
Halliday 2nd Ed Problems - Chapter 30
9. (a) 20 min
(b) 59.4 m(N⋅m)
22. (a) 3750 m/s
(b) drawing
29. (a) 2.60 x 10^6 m/s
(b) 0.109 microseconds
(c) 141 keV
(d) 70.3 kV
31. (-11.4 N/C)i - (6 N/C)j + (4.8 N/C)k
Chapter 30
18. (a) 4.35 mT
(b) 7.53 J/m³
(c) 1.52 microm³
(d) 11.4 microJ
(e) 3.65 microH
(f) same as (d) by a different method
44. (a) (23.4 V)sin((240pi rad/s)t) plus a graph
(b) max EMF = 23.4 V; zero
(c) max I = 124 mA; zero
50. (a) (mu_0)i/(2pir)
(b) [(mu_0)i/(2pir)]l(dr)
(c) [(mu_0)i(l)/(2pi)]ln(b/a)
(d) proof
(e) [(mu_0)i²(l)/(4pi)]ln(b/a)
58. (a) proof
(b) at 5T/8
60. (a) 24.0 mV
(b) 1.55 mA
(c) 72.1 nJ
(d) Q = 5.20 microC; U_L = 18.0 nJ
64. (a) V1 = 33.3 V; V2 = V4 = 16.7 V;  V3 = 0 V
A1 = A3 = 0.333 A; A2 = 0 A
(b) V1 = 38.5 V; V2 = 0; V3 = V4 = 11.5 V
A1 = 0.385 A; A2 = 0.153 A; A3 = 0.230 A
66. (a) V1 = 25 V; V2 = V4 = 50.0 V; V3 = 0 V
A1 = A3 = 0.500 A; A2 = 0 A
(b) V3 = 75.0 V; all other meters read zero
(c) 5.63 microC; long after S is closed
68. (a) 894 microC
(b) 20.0 mJ
(c) graph
70. (a) i1 = 1.50 A; i2 = 1.80 A
(b) 2.40 A
Halliday 2nd Ed Problems - Chapter 31
5. proof
25. (a) 78.5 microT     (b) 1.08 microN⋅m
Chapter 31
(b) 70.6 ohms
(c) resistor - 120 V; capacitor - 450 V;
inductor - 450 V
(d) V4 = 0 V; V5 = 84.9 V
(e) V1 = 27.4 V; V2 = 70.1 V; V3 = 150.4 V;
V4 = 80.3 V; V5 = 84.9 V
(f) V1 = 36.6 V; V2 = 180.6 V; V3 = 104.0 V;
V4 = 76.6 V; V5 = 84.9 V
Wolfson - Chapter 32
9. ((mu_0)l/2pi)ln((a+w)/a)  corrected at 3 PM Wed.
Halliday 2nd Ed Problems - Chapter 32
7. 0.452 V
HRW PROBLEM SUPPLEMENT #1 - CHAPTER 32
28. (a) 1.89 pT
(b) graph; at 10 cm, B = 0.565 pT
38. (a) (4/3) A
(b) at R/4 and at 4R
Chapter 32
14. 15.9 microJ
50. 61.4 kV/m and 205 microT
Halliday 2nd Ed Problems - Chapter 33
11.  (a) 238.7 W  (b) 154.8 W  (c) 393.5 W
12.  (a) 18.7 J   (b) 5.10 J   (c) 13.6 J
Fishbane Problems - Chapter 33
46.  DiffEq is -I(t)R - L(dI/dt) = 0
HRW PROBLEM SUPPLEMENT #1 - CHAPTER 33
50.  100 V  (you must carefully explain why)
HRW PROBLEM SUPPLEMENT #1 - CHAPTER 34
6.  4.74 m
Wolfson - Chapter 34
6.  (a) 7.20 x 10^{11} (V/m)/s
(b) increasing
52.  3.50 gauss
G1 and G2: proofs
Chapter 33
58. (a) 17 on the power line side to 1 on the house side
(b) 39.1 A (rms)
HRW PROBLEM SUPPLEMENT #1 - CHAPTER 33
5.  (a) n(5.00 microseconds) where n=1,2,3,4,...
(b) (2n+1)(2.50 microseconds) where n=0,1,2,3,4,...
(c) (2n+1)(1.25 microseconds) where n=0,1,2,3,4,...
12.  (a) 3.6 mH  (b) 1326 Hz  (c) 189 microseconds
44.  (a) 16.6 Ohms  (b) 422 Ohms  (c) 521 mA
(d) 33.2 Ohms  (e) 408 Ohms  (f) 539 mA
50.  100 V  (you must carefully explain why)
Halliday 2nd Ed Problems - Chapter 36
1.  (a) 5.22 mA  (b) zero
(c) 4.52 mA  (d) taking energy (you must explain why)
2.  (a) 39.1 mA  (b) zero
(c) -33.9 mA (d) supplying energy (you must explain why)
4.  0.6 A for all frequencies
17.  (a) 76.4 mH  (b) yes; 17.8 Ohms; resistor would
consume energy, not store it

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