YOUNG 11e - Chapter 24
32. 563 nJ/m³
Chapter 26
84. (a) 7.10 J
    (b) 3.62 kW
    (c) 1.81 kW
Fishbane Problems - Chapter 28
57. proof
Chapter 29
 2. (a) before - 14.4 micro Wb; after - zero
    (b) 0.360 mV
 6. (a) 0.0302 V + (0.302 mV/s³)t³
    (b) 0.113 mA                  
 7. (d) the EMF direction is CCW
    (e) 0.506 microV
25. (b) towards top of page (clockwise makes
        no sense for the current in the rod)
26. (a) graph
    (b) graph
28. (a) 170 microN/C
    (b) 339 microN/C
    (c) 530 microN/C
    (d) counterclockwise
33. (a) 950 microV
    (b) 109 microH
77. (a) from a to b
    (b) (Rmg)tan(phi)/(L²B²cos(phi))
    (c) (mg)tan(phi)/(LB)
    (d) Rm²g²tan²(phi)/(L²B²)
    (e) same answer as in (d) by a different method
Halliday 2nd Ed Problems - Chapter 29
22. (a) by integration, U_C = (1/2)C(EMF)² and
        energy out from battery = C(EMF)²
    (b) by integration, heat from resistor = (1/2)C(EMF)²
Chapter 30
46. (a) EMF(t)=(23.4 V)sin((240pi rad/s)t) 
        two graphs
    (b) 23.4 V; zero
    (c) 0.124 A; zero
48. (a) (mu_0)i/(2pir)
    (b) Please ignore part (b) (but here is the
        answer: [(mu_0)i/(2pir)]l(dr) )
    (c) [(mu_0)i(l)/(2pi)]ln(b/a)
    (d) trivial proof from part (c)
    (e) [(mu_0)i²(l)/(4pi)]ln(b/a)
62. (a) V1 = 33.3 V; V2 = V4 = 16.7 V;  V3 = 0 V
        A1 = A3 = 0.333 A; A2 = 0 A
    (b) V1 = 38.5 V; V2 = 0; V3 = V4 = 11.5 V
        A1 = 0.385 A; A2 = 0.153 A; A3 = 0.230 A
68. (a) i1 = 1.50 A; i2 = 1.80 A
    (b) 2.40 A
YOUNG 11e - Chapter 30
18. (a) 4.35 mT
    (b) 7.53 J/m³
    (c) 1.52 microm³
    (d) 11.4 microJ
    (e) 3.65 microH
    (f) same as (d) by a different method
66. (a) V1 = 25 V; V2 = V4 = 50.0 V; V3 = 0 V
        A1 = A3 = 0.500 A; A2 = 0 A
    (b) V3 = 75.0 V; all other meters read zero
    (c) 5.63 microC; long after S is closed
68. (a) 894 microC
    (b) 20.0 mJ
    (c) graph (cos function with amp 2.0 A)
    (d) graph (sin function with amp 894 microC)
Halliday 2nd Ed Problems - Chapter 30
 9. (a) 20 min
    (b) 59.4 m(N⋅m)
22. (a) 3750 m/s
    (b) drawing
29. (a) 2.60 x 10^6 m/s
    (b) 0.109 microseconds
    (c) 141 keV
    (d) 70.3 kV
31. (-11.4 N/C)i - (6 N/C)j + (4.8 N/C)k
Wolfson - Chapter 30
42. (a) (mu0)J(|z|)           (b) (mu0/2)Jh
48. (a) (mu0)I(sqrt(n²+(1/2piR)²))
    (b) INVtan(1/2(pi)nR)
57. proof; out of the page
58. proof; out of the page
68. (a) (pi/3)R²J_0 
    (b) (mu0/6r)R²J_0
    (c) (mu0/2)rJ_0(1-(2r/3R))
HRW PROBLEM SUPPLEMENT #1 - CHAPTER 30
73. (a) 4.8 mT
    (b) 0.933 mT
    (c) zero
Fishbane Problems - Chapter 30
32. (a) Bmax = 174 microT; Bmin = 139 microT    <== these answers use
    (b) 0.140 microWb  (1 Wb = 1 T⋅m²)              HRW's value of rho_CU
    (c) heating rate is 1.57 W; doesn't get very hot   (16.9 nOhms⋅m)
    (a) Bmax = 175 microT; Bmin = 140 microT    <== these answers use
    (b) 0.141 microWb  (1 Wb = 1 T⋅m²)              Wolfson's value
    (c) heating rate is 1.58 W; doesn't get very hot  (16.8 nOhms⋅m)
    (a) Bmax = 171 microT; Bmin = 137 microT    <== these answers use
    (b) 0.138 microWb  (1 Wb = 1 T⋅m²)              Y&F's value
    (c) heating rate is 1.54 W; doesn't get very hot  (17.2 nOhms⋅m)
Chapter 31
36. (a) 945 rad/s
    (b) 70.6 ohms
    (c) resistor - 120 V; capacitor - 450 V;
        inductor - 450 V
    (d) V4 = 0 V; V5 = 84.9 V
    (e) V1 = 27.4 V; V2 = 70.1 V; V3 = 150.4 V;
        V4 = 80.3 V; V5 = 84.9 V
    (f) V1 = 36.6 V; V2 = 180.6 V; V3 = 104.0 V;
        V4 = 76.6 V; V5 = 84.9 V
39. (a) use a transformer with half as many
        secondary turns as in the primary
    (b) 6.67 A
    (c) 36 Ohms
YOUNG 11e - Chapter 31
60. C is 2.86 pF; R is 126 mOhms
Halliday 2nd Ed Problems - Chapter 31
 5. proof
25. (a) 78.5 microT     (b) 1.08 microN⋅m
Chapter 32
18. 15.9 microJ
20. (a) 240 microW
    (b) 17.4 V/m
52. 61.4 kV/m and 205 microT
Halliday 2nd Ed Problems - Chapter 32
 7. 0.452 V
Wolfson - Chapter 32
 9. ((mu_0)l/2pi)ln((a+w)/a) 
HRW PROBLEM SUPPLEMENT #1 - CHAPTER 32
28. (a) 1.89 pT
    (b) graph; at 10 cm, B = 0.565 pT
38. (a) (4/3) A  
    (b) at R/4 and at 4R
Chapter 33
28. (a) 63.4 degrees
    (b) 71.6 degrees
34. 32.3 W/cm²
Halliday 2nd Ed Problems - Chapter 33
11.  (a) 238.7 W  (b) 154.8 W  (c) 393.5 W
12.  (a) 18.7 J   (b) 5.10 J   (c) 13.6 J
Fishbane Problems - Chapter 33
46.  DiffEq is -I(t)R - L(dI/dt) = 0
HRW PROBLEM SUPPLEMENT #1 - CHAPTER 33
 5.  (a) n(5.00 microseconds) where n=1,2,3,4,...
     (b) (2n+1)(2.50 microseconds) where n=0,1,2,3,4,...
     (c) (2n+1)(1.25 microseconds) where n=0,1,2,3,4,...
12.  (a) 3.6 mH  (b) 1326 Hz  (c) 189 microseconds
44.  (a) 16.6 Ohms  (b) 422 Ohms  (c) 521 mA
     (d) 33.2 Ohms  (e) 408 Ohms  (f) 539 mA
50.  100 V  (you must carefully explain why)
Wolfson - Chapter 34
 6.  (a) 7.20 x 10^{11} (V/m)/s
     (b) increasing
20.  (a) 3.00 m   (b) 10.0 cm
     (c) 500 nm   (d) 0.300 nm
HRW PROBLEM SUPPLEMENT #1 - CHAPTER 34
 6.  4.74 m
40.  (a) 15.9%  (b) 84.1%
Knight 2nd Ed - Chapter 35
24.  (a) 3.33 microT
     (b) 1.67 microT in the negative x direction
     (c) 50 m
Halliday 2nd Ed Problems - Chapter 36
 1.  (a) 5.22 mA  (b) zero
     (c) 4.52 mA  (d) taking energy (you must explain why)
 2.  (a) 39.1 mA  (b) zero
     (c) -33.9 mA (d) supplying energy (you must explain why)
 4.  0.6 A for all frequencies
17.  (a) 76.4 mH  (b) yes; 17.8 Ohms; resistor would
                      consume energy, not store it
Knight 2nd Ed - Chapter 36
67.  (a) 2.50 Ohms
     (b) 1.93 microF   <= misprint corrected 8/05
     (c) 50900 rad/s   <= misprint corrected 8/05
G1 and G2: proofs