How much Ca, C, O in the writing?

• 0.025 g x 1 mol/100.08 g = 0.00025 mol CaCO3

• 0.00025 mol CaCO3 contains 0.00025 mol Ca, 0.00025 mol C, 0.00075 mol O

• 0.00025 mol Ca x 40.08 g/mol = 0.0100 g Ca

• 0.00025 mol C x 12.01 g/mol = 0.00300 g C

• 0.00075 mol O x 16.00 g/mol = 0.0120 g O

• sum = 0.0100 + 0.00300 + 0.0120 = 0.0250 g

Previous slide

Next slide

Back to first slide

View graphic version