First calculate the heat and work. Since this is an isothermal ideal gas, the change in internal energy is zero and q = -w. w = -PexDV = -(1 mole)(1 atm)(9 liters)(101 J/(atm l)) = -909 J. Thus q is 909 Joules. Now we can do the calculations:

We calculate the DSsys from the amount of heat that would be transferred if the process had gone reversibly: . We can next calculate DSsur from the heat that is taken up from the environment: . Finally the free energy change for an increase in volume at constant temperature in an ideal gas can be determined as: