Conceptual Problems. For these five problems, you do not need to justify or explain your answer. Each problem is worth 5 points
Cu2+(aq)+ SO42-+ Zn(s) ß à Cu(s) + Zn2+(aq) + SO42-(aq)
is spontaneous. Is the standard potential for this reaction greater than zero, less than zero, equal to zero or impossible to determine?
Numerical Problems. You must show all your work for complete credit.
7. (20 points) Let's say that a galvanic cell (spontaneous oxidation/reduction reaction like a battery) is constructed using the half reactions Cu2+(aq) + 2e- à Cu(s) (E0 = +0.34V) and Zn2+ + 2e- à Zn(s) (E0 = -0.76V). What ratio of concentrations, Zn2+/Cu2+, in the electrolyte will be required if one wants a 1.10 V zero current potential? Assume that the temperature is 298 K and that all activity coefficients are one. Hint: What is Q in the Nernst Equation for this reaction?
8. (20 points) For the elementary reaction series A+B à C ß à D, for components C and D only, give
Note that the initial concentrations are A0 = B0= 0.30 M, C0 = 0.20 M, D0 = 0.00 M. The rate constant for the first reaction, k1, is 30 M-1 s-1, the forward rate constant for the second reaction, kf2, is 15 s-1 and the reverse rate constant, kb2, is 10 s-1.
Applied Problem. You must show all your work for complete credit.
9. (15 points) The purpose of a catalyst is to lower the activation energy of a reaction (in fact, that is all that a catalyst does). The enzymes in your body which mediate chemical reactions are catalysts. One of these enzymes is called catalase and it catalyzes the breakdown of hydrogen peroxide: 2H2O2 (hydrogen peroxide) à 2H2O + O2. At 20 C, the uncatalyzed rate of this reaction is quite slow, taking days to weeks for an open bottle of hydrogen peroxide to decay. When the enzyme is added, the rate increases by a factor of 108 at the same temperature (in other words, ). Assuming that the rate is related to the activation energy in the usual way (k is proportional to ), determine how much the enzyme lowers the activation energy for this reaction.