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TEST 1 (MAT 343)

Instr. S. Nikitin

ASU ID:..................................NAME:..................................

1. Find all of the solutions, if any exist, for the following systems.

System 1:

\begin{eqnarray*}
&&4\cdot x_1+x_2=1 \\
&&x_1+4\cdot x_2+x_3=1 \\
&&x_2+4\c...
...=-1 \\
&&x_4+4\cdot x_5+x_6=1 \\
&&x_5+4\cdot x_6=1 \\
&&
\end{eqnarray*}

System 2:

\begin{eqnarray*}
&&-2\cdot x_1+x_2=1 \\
&&x_1-2\cdot x_2+x_3=1 \\
&&x_2-x_...
...-1 \\
&&x_3-2\cdot x_4+x_5=1 \\
&&x_4-2\cdot x_5=1. \\
&&
\end{eqnarray*}

System 3:

\begin{eqnarray*}
x_1+4\cdot x_2+5\cdot x_3 &=&1 \\
2\cdot x_1+4\cdot x_2+x_3 &=&1 \\
4\cdot x_1+4\cdot x_2+x_3 &=&2.
\end{eqnarray*}

System 4:

\begin{eqnarray*}
x_1+ x_2-x_3 &=&2 \\
-2\cdot x_1+2\cdot x_2+x_3 &=&1 \\
3\cdot x_1+2\cdot x_2+x_3 &=&10.
\end{eqnarray*}

System 5:

\begin{eqnarray*}
2x_1+ x_2+x_3 +x_4 &=&2 \\
2x_1- x_2+2x_3-2x_4 &=&0 \\
2x_1+ x_2+4x_3+4x_4 &=&1 \\
2x_1- x_2+8x_3-8x_4 &=&1
\end{eqnarray*}

System 6:

\begin{eqnarray*}
x_1+ 3\cdot x_2+x_3 +x_4 &=&2 \\
x_1- 3\cdot x_2+x_3-x_4 &=...
... 3\cdot x_2+4x_3+4x_4 &=&0 \\
x_1- 3\cdot x_2+7x_3-8x_4 &=&1
\end{eqnarray*}

2.Given matrices $A,\;\;B$ calculate $A\cdot B.$

a) $A=\left(
\begin{array}{cc}
0 & 1 \\
-1 & 0 \\
1 & 0
\end{array}
\right...
...
\begin{array}{cccc}
1 & 0 & -1 & 0 \\
1 & 1 & 0 & 1
\end{array}
\right) .$

b) $A=\left(
\begin{array}{cccc}
-1 & 1 & 0 & 0 \\
2 & -1 & 1 & 0 \\
0 & 0 &...
... -1
\end{array}
\right) .
\begin{array}{cc}
& \\
& \\
&
\end{array}
$

c) $A=\left(
\begin{array}{cccc}
0 & 1 & 1 & 1 \\
1 & 0 & 1 & 1 \\
1 & 1 & 0...
... 1 & 0 \\
1 & -1 & 0 \\
0 & 1 & 0 \\
1 & -1 & 1
\end{array}
\right) .
$

3.Given a matrix $A$ find $A^{-1}.$

a) $A=\left(
\begin{array}{cccc}
2 & 1 & 0 & 0 \\
1 & 2 & 1 & 0 \\
0 & 1 & 2 & 1 \\
0 & 0 & 1 & 2
\end{array}
\right) .
$ b) $A=\left(
\begin{array}{ccccc}
3 & 1 & 0 & 0 & 0 \\
1 & -1 & 1 & 0 & 0 \\ 
...
...& 0 \\
0 & 0 & 1 & -1 & 1 \\
0 & 0 & 0 & 1 & -1
\end{array}
\right) .
$

4.Use Cramer's Rule to find the solution of the systems


\begin{displaymath}
\begin{array}{cccccc}
3\cdot x_1+ & x_2+ & x_3+ &x_4& = & ...
...+ & x_3+ &3x_4& = & 1 \\
& & & & \\
& & & &
\end{array}
\end{displaymath}


\begin{displaymath}
\begin{array}{cccccc}
4x_1+ & x_2+ & x_3+ &4x_4& = & 1 \\ ...
...+ & x_3+ &4x_4& = & 1 \\
& & & & \\
& & & &
\end{array}
\end{displaymath}

5.Calculate the following determinants.

\begin{displaymath}
\det \left(
\begin{array}{cccc}
3 & 1 & 0 & 1 \\
1 & 3...
... \\
0 & 0 & 4 & 1 \\
1 & -2& 1 & 4
\end{array}
\right),
\end{displaymath}


\begin{displaymath}
\det \left(
\begin{array}{ccccc}
3 & 1 & 0 & 0 & 1 \\
...
... 8 & 0 & 5 & 1 \\
1 & 16 & 0 & 0 & 5
\end{array}
\right)
\end{displaymath}

6. Find all solutions (if any exist) for the following linear systems.

\begin{eqnarray*}
-3\cdot x_1+ x_2+x_3 +x_4 &=&1 \\
2x_1- 3x_2+x_3 &=&0 \\
-x_1- x_2+3x_3-x_4 &=&1 \\
x_1- 2x_2+x_3 &=&0
\end{eqnarray*}

\begin{eqnarray*}
x_1+ 2x_2+3x_3 +4x_4 &=&0 \\
4x_1- 4x_2+2x_3 &=&0 \\
x_1+ 2x_2+4x_3+4x_4 &=&0 \\
x_1- x_2+8x_3 &=&0
\end{eqnarray*}





Sergey Nikitin 2011-02-16